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Grade: 12th pass
        
How much 0.5N HCl require to neutralise  35 gm
0.5N KOH
2 months ago

Answers : (1)

Sandeep Mishra
askIITians Faculty
27 Points
							
1 mole of KOH reacts with 1 mole of HCl . Therefore, 56 gram of KOH reacts with 36.5 gram of HCl. So, for 35 gram of KOH will react with the following mass of HCl = (35*36.5)/56= 22.8125
one month ago
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