Grade upto college level Inorganic Chemistry
How many grams of CaO are required to neutralize 852 gm of P4O10? Draw structure of P4O10 molecule.
How many grams of CaO are required to neutralize 852 gm of P4O10? Draw structure of P4O10 molecule.
1 Answer
Navjyot Kalra
6CaO + P4O10 → 2Ca3 (PO4)2
Moles of P4O10 = 852/284 = 3
Moles of CaO = 3 * 6 = 18
Wt. of CaO = 18 * 56 = 1008 g
For structure of P4O10 : See question 20 of this Section.
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