HOW MANY GEOMETRICAL ISOMERS OF k4[feCl2Br2(CN)2} ?
aasam , 7 Years ago
Grade 12th pass
Inorganic Chemistry> HOW MANY GEOMETRICAL ISOMERS OF k 4 [feCl...
1 Answers
varun
Last Activity: 7 Years ago
HELLO,
Total geometrical isomers in K4[FeCl2Br2(CN)2] are 5
because since it is an octahedral compound of the form MA2B2C2 where A,B,C represents the ligands so the geometrical isomers comes out to be as 5 and optical isomers are 2
Totally there are 7 isomers
THANK YOU
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