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HOW MANY GEOMETRICAL ISOMERS OF k 4 [feCl 2 Br 2 (CN) 2 } ?

HOW MANY GEOMETRICAL ISOMERS OF k4[feCl2Br2(CN)2} ?

Grade:12th pass

1 Answers

varun
304 Points
4 years ago
HELLO,
Total geometrical isomers in K4[FeCl2Br2(CN)2] are 5 
because since it is an octahedral compound of the form MA2B2C2 where A,B,C represents the ligands so the geometrical isomers comes out to be as 5 and optical isomers are 2
Totally there are 7 isomers
THANK YOU

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