Navjyot Kalra
Last Activity: 10 Years ago
At first Bi(NO3)3 hydrolyses to give nitric acid which, being an oxidizing agent, oxidizes potassium iodide liberating free iodine responsible for dark brown precipitate. Iodine dissolved in excess of potassium iodide forming soluble KI3 imparting yellow colour to solution.
Bi(NO3)3 + H2O → [Bi(OH)(NO3)2] + HNO3
NO3‑ + 4 H+ + 3e- → NO2 + 2H2O] * 2
Ki + I2 → KI3
(yellow solution)