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For the reaction 2HI→H2+I2,the degree of dissociation(alfa) of HI is related to the equilibrium constant ( kp ) by the expression

For the reaction 2HI→H2+I2,the degree of dissociation(alfa) of HI is related to the equilibrium constant ( kp ) by the expression

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Grade:11

2 Answers

Vikas TU
14149 Points
5 years ago
                  2HI             →         H2         +            I2
t=teq.            C(1-a)                         Ca/2                          Ca/2
Kp = (Ca/2)^2/(C(1-a))^2 => a^2/4(1-a)^2
a/(1-a) = 2root(Kp)
a = 2root(Kp) – 2root(Kp)*a
a(1 + 2root(Kp)) = 2root(Kp)
a = 2root(Kp)/(1 + 2root(Kp))
ankit singh
askIITians Faculty 614 Points
one year ago
For the reaction 2HI--H2+I2 the degree of dissociation (a) of HI is related to equilibrium constant Kp by the expression. Answer: ... Yes it is an reversible reaction.

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