0

Guest

Courses New

For the reaction 2HI→H2+I2,the degree of dissociation(alfa) of HI is related to the equilibrium constant ( kp ) by the expression

For the reaction 2HI→H2+I2,the degree of dissociation(alfa) of HI is related to the equilibrium constant ( kp ) by the expression

Question Image
Grade:11

2 Answers

Vikas TU
14149 Points
7 years ago
                  2HI             →         H2         +            I2
t=teq.            C(1-a)                         Ca/2                          Ca/2
Kp = (Ca/2)^2/(C(1-a))^2 => a^2/4(1-a)^2
a/(1-a) = 2root(Kp)
a = 2root(Kp) – 2root(Kp)*a
a(1 + 2root(Kp)) = 2root(Kp)
a = 2root(Kp)/(1 + 2root(Kp))
ankit singh
askIITians Faculty 614 Points
3 years ago
For the reaction 2HI--H2+I2 the degree of dissociation (a) of HI is related to equilibrium constant Kp by the expression. Answer: ... Yes it is an reversible reaction.

Think You Can Provide A Better Answer ?

Other Related Questions on Inorganic Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More