for the first reaction process A+B--product , the

Question

for the first reaction process A+B-->product , the rate is first order with respect to A and second order with respect to B. if 1 mol each of A and B were introduced into a 1L besak, and the initial rate were 1×10^-2 mol/L /sec . calculate the rate when half the reactants have been turned into products

Arun · Accepted Answer

Dear student A +B = ProductInitial number of moles of A = 1 mol and For B = 1 molInitial volume = 1 litreInjtial rate = 10^-2Thus the rate equation can be written as-Rate = k [a]¹ [b]²Where k is the rate constantk = 10^-2Now when half of the reactants have been converted into product.a = 0.5, b = 0.5Thua the rate will beRate = k [0.5]¹ [0.5]²= k/8= 10^-2/8 = 125 * 10^-5

Inorganic Chemistry> for the first reaction process A+B-->prod...

shivani priya , 7 Years ago

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Inorganic Chemistry> for the first reaction process A+B-->prod...

shivani priya , 7 Years ago

Arun

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