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First and second ionisation energies of magnesium are 7.646&15.035 eV respectively.the amount of energy needed to convert all the atoms of magnesium into Mg2+ ions present in 12 mg of magnesium vapours is

First and second ionisation energies of magnesium are 7.646&15.035 eV respectively.the amount of energy needed to convert all the atoms of magnesium into Mg2+ ions present in 12 mg of magnesium vapours is

Grade:12

1 Answers

varun
304 Points
3 years ago
HELLO ABHUSHEK,
Total energy needed to convert one Mg atom into Mg2+ gas ion = IE1 + IE2
                                                                                                     =  7.646 + 15.035
                                                                                                      = 22.681 eV
                                                                                                       => 2188.6Kj/mol
12 mg of Mg = 0.5 X 10^-3 mol
therefore,
total energy = 0.5 X 10^-3 X 2188.6
                  =          1.0943Kj
THANK YOU

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