explain the geometry of CIF3 and NH3 using vsepr theory.
explain the geometry of CIF3 and NH3 using vsepr theory.
Vivek Prasad Dalbehera , 8 Years ago
Grade 11
Inorganic Chemistry> explain the geometry of CIF3 and NH3 usin...
1 Answers
Umakant biswal
Last Activity: 8 Years ago
@ vivek
acc to VSEPR theory the molecule CIF3 have T shaped structure and its based upon trigonal bipyramidal structure .
u have to remember these things here
1- here the central atom is O ..
2- the cl contributes 7 electrons and the total valence shell electron is 10 and if VSEP are concerned then its 5 pair .
3- the lone pair occupy equitoraial structure on trigonal bypyramid .
this minimise the no. of 90 degree lp-bp interactions .
4- the equitorial axial bond angle are less than 90 degree , due to lp-bp repulsion being greater than bp-bp repulsion .
AND IN NH3 ACC TO VSEPR THEY HAVE TRIGONAL PYRAMIDAL STRUCTURE ..
THE CENTRAL ATOM IS N THERE AND TOTAL VSEP ARE 4 , AND VSE ARE 8 .
BOND ANGLE = 107 DEGREE (LESS THAN 109 DUE TO LP-BP REPULSION .
BEING GREATER THAN BP-BP REPULSION )
HOPE IT CLEARS YOUR DOUBT
acc to VSEPR theory the molecule CIF3 have T shaped structure and its based upon trigonal bipyramidal structure .
u have to remember these things here
1- here the central atom is O ..
2- the cl contributes 7 electrons and the total valence shell electron is 10 and if VSEP are concerned then its 5 pair .
3- the lone pair occupy equitoraial structure on trigonal bypyramid .
this minimise the no. of 90 degree lp-bp interactions .
4- the equitorial axial bond angle are less than 90 degree , due to lp-bp repulsion being greater than bp-bp repulsion .
AND IN NH3 ACC TO VSEPR THEY HAVE TRIGONAL PYRAMIDAL STRUCTURE ..
THE CENTRAL ATOM IS N THERE AND TOTAL VSEP ARE 4 , AND VSE ARE 8 .
BOND ANGLE = 107 DEGREE (LESS THAN 109 DUE TO LP-BP REPULSION .
BEING GREATER THAN BP-BP REPULSION )
HOPE IT CLEARS YOUR DOUBT
ALL THE BEST .,.
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