Kevin Nash
Last Activity: 10 Years ago
The solubility products of CuS and ZnS are
K base sp(CuS) = 10^-38 and K base sp (ZnS) =
10^-22
Since K base sp (CuS) << K base sp
(ZnS), very small concentration of S^2 is sufficient to cause the precipitation
of Cu^2+ ions. In order to have very small concentration of S^2- ions, acidic
medium is used. Due to the common ion H^+, the ionization of H base 2S is
suppressed:
H base 2S ? 2H^+ +S^2-
The available concentration of S^2- ions in
acidic medium causes only the precipitation of CuS and not that of ZnS.