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The solubility products of CuS and ZnS are
K base sp(CuS) = 10^-38 and K base sp (ZnS) = 10^-22
Since K base sp (CuS) << K base sp (ZnS), very small concentration of S^2 is sufficient to cause the precipitation of Cu^2+ ions. In order to have very small concentration of S^2- ions, acidic medium is used. Due to the common ion H^+, the ionization of H base 2S is suppressed:
H base 2S ? 2H^+ +S^2-
The available concentration of S^2- ions in acidic medium causes only the precipitation of CuS and not that of ZnS.
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