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Draw the molecular structures of XeF2, XeF4 and XeO2F2 indicating the location of lone pair(s) of electrons.

Amit Saxena , 10 Years ago
Grade upto college level
anser 1 Answers
Navjyot Kalra

Last Activity: 10 Years ago

Use the formula
H(hydridisation), H = 1/2 (V + M – C + A) where
V = number of electron in valence shell of central atom
M = number f monovalent atoms surrounding the central atom
C = Charge on cation
A = Charge on anion
XeF2 : H = 1/2 (8 + 2 – 0 + 0) = 5 Hence hybridization is sp3d, and thus its structure is linear.
XeF4 : H = 1/2 (8 + 4 – 0 + 0) = 6, Hence hybridization is sp3d2 and thus its structure is square planar.
XeO2F2 : H = 1/2 (8 + 2 – 0 + 0) = 5, Hence hybridization is sp3d and shape is see saw.
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