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Derive the eqn : dG=VdP-sdT..................................

Manav , 8 Years ago
Grade 11
anser 2 Answers
Vikas TU
Diffrentiate:  G = H - TS
we get, dG = dH - d(TS) = dH - TdS - SdT. 
After, differentiating H = U + pV
we get, dH = dU + pdV + Vdp.
Also, dU = dq + dw = dq - pdV,
so dH = dq + Vdp.
hence, we get the final eqn. as
: dG = dq + Vdp - TdS - SdT
 
Last Activity: 8 Years ago
S S
The first answer is correct throughout except for the last part....We know, that dS=dq/THence the final equation becomesdG=VdP-SdT+dq-Tdq/T=>dG=VdP-SdT .
Last Activity: 8 Years ago
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