MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
Deduce the following relationships
Da=Pdv-sdt 
Dg =tds +vdp 
4 months ago

Answers : (1)

Arun
19181 Points
							
We have seen that the internal energy is
conserved and depends on mechanical (dw) and thermal (dq) energy. Given that pressure‐volume work done by the system is dw = ‐PdV and that the entropy change can be expressed as dS = dq/T (i.e. dq = TdS) we can express the internal energy as
dU = TdS – pdV
By a transformation of variables we define H = U + PV or dH = d(U+PV) = dU + PdV + VdP. Therefore,
dH = TdS + VdP
4 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 54 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details