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Grade 12Inorganic Chemistry

Consider the reaction: 6NaOH +3Cl2 -------> 5NaCl + A + 3H2O. The oxidation number of chlorine in “A” is:(EAMCET 2001 M)

1) Iron

2) Carbon

3) Mercury

4) Nickel

Profile image of sneha singh
12 Years agoGrade 12
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1 Answer

Profile image of Sunil Kumar FP
11 Years ago
3Cl2 +6NaOH --> NaClO3 +5NaCl +3H2O
It is a disproportionation reaction. . Disproportionation is the simultaneous oxidation and reduction of the same species.
In terms of oxidation state changes, the chlorine disproportionates from 6 Cl (0, element) to 5 Cl (-1, chloride ion) plus 1 Cl [+5, chlorate (V)ion ] Overall 5 electrons gained,

The 'chlorine' in the chlorate ion disproportionates from 3 Cl(+1) to 2 Cl(-1, chloride ion) plus 1Cl(+5, chlorate(V) ion). Overall 4 electrons gained


thus its oxidation number is +5

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