Navjyot Kalra
Last Activity: 10 Years ago
Since B2O3 is formed by reaction of (Y) with air, (Y) therefore should be B2H6 in which % of hydrogen is 21.72. The compound (X) on reduction with LiAIH4 gives B2H6. Thus it is boron trihalide. The reactions are show as:
4BX3 + 3LiAIH4 → 2B2H6 + 3LiX + 3AIX3
(X) (Y) (X = CI or Br)
B2H6 + 3O2 → B2O6 + 3H2O + heat
(Y)
Structure of B2H6 is as follows:
Thus the diborane molecular has four tow-centre- two – electron bonds (2c – 2e bonds) also called usual bonds and two three -centre -two –electron bonds (3c – 2e) also called banana bonds. Hydrogen attached to usual and banana bonds are called Ht (terminal H) and Hb (bridge H) respectively.