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canyou pleasegivve answer for this”pure o2 diffuses through an aperture in 224 seconds, wheres mixture of o2 and anther gas containing 80% o2 diffuses from the same in 234sec what is the molecular weight of gas?” please mail the answer to the given mail.

canyou pleasegivve answer for this”pure o2 diffuses through an aperture in 224 seconds, wheres mixture of o2 and anther gas containing 80% o2 diffuses from the same in 234sec what is the molecular weight of gas?”please mail the answer to the given  mail.

Grade:11

1 Answers

Arun
25750 Points
5 years ago
I can't mail you as you have asked here.
 

For gaseous mixture 80% O2, 20% of other gas m   

Average molecular weight Mm = 32 (for O2) × 80 + 20 × m / 100   

Now, for diffusion of gaseous mixture and pure O2   

rO2 / rm = √Mm / MO2 or VO2 / EO2 × Em / Vm = √Mm / MO2   

∴ 1 / 224 × 234 / 1 = √Mm / 32 

∴ Mm= 34.92  

∴ 32 × 80 + 20 × m / 100 = 34.92   

∴ m = 46.6

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