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can you explain why lead 2 chloride dissolve in conc HCL acid to give a solution which after treatment with chlorine in the cold gives a yellow precipitates when ammonium chloride

irene , 4 Years ago
Grade 12
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TEJA KRISHNA

Last Activity: 4 Years ago

Addition of chloride ions to a suspension of PbCl2 gives rise to soluble complex ions. In these reactions the additional chloride (or other ligands) break up the chloride bridges that comprise the polymeric framework of solid PbCl2(s).

(aq)2−]4 → [PbCl + 2 Cl2(s)PbCl (aq)]3 → [PbClCl + 2(s)PbCl

PbCl2 reacts with molten NaNO2 to give PbO:

 + 2 NO + 2 NaCl3 → PbO + NaNO2 + 3 NaNO2(l)PbCl

PbCl2 is used in synthesis of lead(IV) chloride (PbCl4): Cl2 is bubbled through a saturated solution of PbCl2 in aqueous NH4Cl forming [NH4]2[PbCl6]. The latter is reacted with cold concentrated sulfuric acid (H2SO4) forming PbCl4 as an oil.[11]

Lead(II) chloride is the main precursor for organometallic derivatives of lead, such as plumbocenes.[12] The usual alkylating agents are employed, including Grignard reagents and organolithium compounds:

[13] + Pb + 6 MgBrCl3Pb-PbR3 + 6 RMgBr → R23 PbCl Pb + Pb + 4 MgBrCl4 + 4 RMgBr → R22 PbCl Pb + 4 LiCl + Pb4 + 4 RLi → R22 PbCl

These reactions produce derivatives that are more similar to organosilicon compounds, i.e. that Pb(II) tends to disproportionate upon alkylation.

PbCl2 can be used to produce PbO2 by treating it with sodium hypochlorite (NaClO), forming a reddish-brown precipitate of PbO2.

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