Calculate total permanent and temporary hardness if 50 ml of water sample consumed 18 ml of 0.01M edta before boiling and 7ml of 0.01 edta after boiling

Dear Student,
50ml of water sample=15ml of 0.01M EDTA

= 100ml of 0.01 EDTA=300ml of 0.01M EDTA

=2*300ml of 0.01 N EDTA

=600 ml or 0.6 L of 0.01 eq. of CaCO3

=0.6*0.01*50g CaCO3 eq.

Then the total hardness=0.30g or 300mg of CaCO3 eq=300mg/L or ppm

now 50 ml of boiled water=5 ml of 0.01 M EDTA

1000ml of boiled water= 100 ml of 0.01 M EDTA

=100 mL of 0.01 M EDTA

=200ml or 0.2 L of 0.01 N EDTA

=0.2*0.01*50 g of CaCO3 eq

=0.1 g or 100mg of CaCO3 eq

permanent hardness=100mg/L or ppm

Temporary hardness=300-100= 200ppm