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`        Calculate the Osmotic pressure of 0.9 % aqueous solution of solute X at 25 degree Celsius Molar mass of the solute is 60 gram per mole.(R = 0.0820 lit-atm K^-1 mol^-1).`
2 years ago

## Answers : (1)

neelam
108 Points
```							0.9% of  aqueous solution  of solute means 0.9 gram of solute X present in 100 gram of solution.  It means given weight of solute is 0.9 gram.  Formula of osmotic pressure isPi = n/v RT.  Put the value of n= 0.9/60(given weight of solute /molar mass of solute) ,v=100, R= 0.0820 and find the answer. OK
```
2 years ago
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions