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Calculate the molar solubility of Mg(OH) 2 in 1MNH 4 Cl K sp Mg(OH) 2 = 1.8 10 –11 K b (NH 3 ) = 1.8 10 –5
Dear Student Mg(OH)2(s) +2NH4+ ===== Mg++ + 2NH4OH1M x 2x let molar solubility of Mg(OH)2 be x in 1 M NH4Cl 1.8 * 10^-11 / 1.8*1.8*10^-10 = x* (2x)^2 / 1^2 = 4 x^3/1 = 0.1/1.8 = 1/18x = 0.24 M regardsArun (askIITians forum expert)
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