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Grade: 11

                        

Calculate the molar solubility of Mg(OH) 2 in 1MNH 4 Cl K sp Mg(OH) 2 = 1.8 10 –11 K b (NH 3 ) = 1.8 10 –5

2 years ago

Answers : (1)

Arun
24742 Points
							
Dear Student
 
Mg(OH)2(s) +2NH4+  ===== Mg++  + 2NH4OH
1M                     x                       2x
 
let molar solubility of Mg(OH)2 be x in 1 M NH4Cl
 
1.8 * 10^-11 / 1.8*1.8*10^-10    = x* (2x)^2 / 1^2 = 4 x^3/1 = 0.1/1.8 = 1/18
x = 0.24 M
 
regards
Arun (askIITians forum expert)
 
 
2 years ago
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