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The expression of energy is given by,
Where,
Z = atomic number of the atom
n = principal quantum number
For ionization from n1 = 5 to ,
Therefore ΔE = E2- E1 = - 21.8 X10-19 (1/n22-1/n12)
= 21.8 X10-19(1/n22-1/n12)
= 21.8 X10-19 (1/52-1/∞)
= 8.72 x 10-20 J
For ionization from 1st orbit, n1= 1,
Therefore ΔE’ = 21.8x10-19(1/12-1/∞)
= 21.8x10-19 J
Now ΔE’/ ΔE = 21.8x10-19 / 8.72x10-20 = 25
Thus the energy required to remove electron from 1st orbit is 25 times than the required to electron from 5th orbit.
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