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CALCULATE THE AMOUNT OF (C6H5COOH) REQUIRED FOR PREPARING 250mL OF 0.15M SOLUTION IN METHANOL

CALCULATE THE AMOUNT OF (C6H5COOH) REQUIRED FOR PREPARING 250mL OF 0.15M SOLUTION IN METHANOL 

Grade:11

1 Answers

Vikas TU
14149 Points
4 years ago
C6H5COOH is n Methanol means 250*0.15/1000 moles are required .
Molar mass of  benzoic acid is => 122 g
Hence, mass of benzoic acid => 122*250*0.15/1000 = 4.575 gms.

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