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Grade: 12th pass


Bond angle order of no2, no2-, no2+,no3- in decreasing order

2 years ago

Answers : (3)

24742 Points
NO2- 3- 2 2+ 

For NO2-, the molecule is bent but we have 1 lone pair on nitrogen. Lone pair electron repulsion is more than the bonding electrons so the bond angle will be less than 120o.
In NO3-, there is no lone pair of electrons, all are bonding pairs leading to an ideal bond angle of 120o.
In NO2the one lone electron exerts a less repulsion than a lone pair of electrons, so two bonding oxygen atoms are able to spread out more leading to bond angle greater than the ideal of 120o.
In NO2+, there is no lone pair, only bond pairs so the molecule is linear leading to a bond angle of 180o.
2 years ago
108 Points
An easy way to calculate bond order is:
Bond Order=Valancy of peripheral atom + (Charge on whole atom) / No. Of peripheral atoms. 
Example :
For No2-, peripheral atom here is oxygen
Bond order = 2 + (-1)/2 
                    =2 - 0.5 = 1.5
2 years ago
Kushagra Madhukar
askIITians Faculty
605 Points
Hello student
The pictorial representation of the species mentioned and their respective angle in ascending order is as shown.
Let’s analyse each specie individually
NO2- → In this the hybridisation of central N atom is sp2, which accounts for 120o bond angle, but since the repulsion given by the lone pair of electrons is greater than the bond pair electrons, the O-N-O bond angle decreases and attains a value lesser than 120o
NO3- → In this the hybridisation of central N atom is sp2 and also there is no lone pair and only bond pair of electrons(which also undergo resonance and equalises bond order), therefore the angle between O-N-O remains unchanged and is equal to 120o
NO2 → In NO2, instead of having a lone pair of electrons it only has a single elecron in its lone pair, which gives lesser repulsion to the O-N-O bond, even lesser than the bond pair – bond pair repulsion, therefore the O-N-O bond readjusts and its angle increases and attains a value greater than 120o
NO2+ → In NO2+, the central N atom is sp hybridised and there is no lone pair on N atom, thus the angle between O-N-O bond becomes 180o
Therefore the order of angle is- NO2- 3- 2 2+
4 months ago
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