×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Binding energy of electrons in a metal is 250kJ/mol. Then threshold frequency of metal is?


3 years ago

Khushi goyal
49 Points
							electron binding energ also called ionisation potential is the energy required to remove an electron from an atom ,a molecule or an ion/. accordingly ou can work out threshold frequency by using E=hv  wher E is the bindinjg energy.I hope this clear to you. PLEASE HIT THE APPROVED BUTTON THEN.

3 years ago
Arun
25768 Points
							binding energy of electron = 250KJ/molbinding energy of 1 electron = 250 * 103/6.023 * 1023  J = 4.15 * 10 –19 Jbinding energy = hv0v0 is thresold frequency4.15 * 10 –19  =  6.625 * 10 –34 * v0v0 = 6 * 1014  sec –1

3 years ago
Shailendra Kumar Sharma
188 Points
							Binding energy of electron =250kJ/molso Binding energy per electron =250*103/(6.023X1023)=4.15X10^-19Thus the h$\nu$ =4.15X10-19 thus $\nu$ =6.27 X 1014 sec-1

3 years ago
RAHUL GURJAR
42 Points
							answerebinding energy of electron = 250KJ/molbinding energy of 1 electron = 250 * 103/6.023 * 1023  J = 4.15 * 10 –19 Jbinding energy = hv0v0 is thresold frequency4.15 * 10 –19  =  6.625 * 10 –34 * v0v0 = 6 * 1014  sec –1

3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Inorganic Chemistry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 54 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions