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BF4- exists but BCl4- , BBr4- , BI4- doesn't?? AS Boron has vacant p orbital.. as in bf4- it accepts e- pair from f- .. in smiliar way it can accept e- from Cl- and Br-... Plz explain

BF4- exists but BCl4- , BBr4- , BI4- doesn't??
AS Boron has vacant p orbital.. as in bf4- it accepts e- pair from f- .. in smiliar way it can accept e- from Cl- and Br-... Plz explain

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2 Answers

Arun
25750 Points
4 years ago
Boron is a group three element that only forms 3 bonds. You could possibly have BCl3. Plus B is quite small and Cl is pretty large, so even if it could form a fourth bond, which it can't, there would be a lot of strain from overlapping van der waals radii.
Shreya tyagi
13 Points
3 years ago
In Bcl4- ,there is bulky group attached i.e cl which creates hindrance around boron so this borate anion does not seem to exist

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