Grade 11Inorganic Chemistry
BF3 reacts with (CH3)3 N to form an adduct (CH3)3N BF3 . The bond length of B – F bond in the adduct is
BF3 reacts with (CH3)3 N to form an adduct (CH3)3N BF3 . The bond length of B – F bond in the adduct is
1 Answer
Yash Patari
dear student,
In BF3,thereis back bonding in between fluorinc and boron due to presence of p-orbital in boron. back bonding imparts doublebond characteristics. As BF3forms adjuct theback bonding is no longer present and thus double bond characteristic disappears. Hence, bond becomes a bit longer than earlier ( 1.30Å). the-bond-length-is-30-when-is-bf3-is-allowed-to-be-treated-withe-me3n-it-forms-an-adduct
In BF3,thereis back bonding in between fluorinc and boron due to presence of p-orbital in boron. back bonding imparts doublebond characteristics. As BF3forms adjuct theback bonding is no longer present and thus double bond characteristic disappears. Hence, bond becomes a bit longer than earlier ( 1.30Å). the-bond-length-is-30-when-is-bf3-is-allowed-to-be-treated-withe-me3n-it-forms-an-adduct
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