Inorganic Chemistry> Atomic radii of fluorine and neon in Angs...

Atomic radii of fluorine and neon in Angstrom units are respectively given bya. 0.72, 1.60b. 1.60, 1.60c. 0.72, 0.72d. None of these

Shane Macguire , 10 Years ago

Grade upto college level

7 Answers

Jitender Pal

Last Activity: 10 Years ago

Sol. First ionization energy of oxygen is less than that of nitrogen on the ground of stability of valence shell configuration, hence, (a) is the correct answer.

Hitesh munot

Last Activity: 7 Years ago

According to general trend in a period atomic radius decreases but neon`s numeric value of atomic radius is greater than fluorine because neon`s Vander Waal radius is calculated and fluorine`s covalent radius is calculated.So correct answer is `a`

Ramakrishna

Last Activity: 6 Years ago

Ans is option A. Fluorine is calculated covelent radii neon is calculated vanderwal radii vanderwal greater than covalent radii

Shallini Maheshwari

Last Activity: 6 Years ago

The radii of noble gas elements are "Van Der wal's radii". Hence, Neon's atomic radius must be much more than that of fluorine. And it is not possible to get covalent and metallic radii for noble gases. Van Der wal's radii is greater then covalent radii. Where fluorine is covalent radii and neon is van der Wal radii. So, the answer is (A).

Tarun Mahajan

Last Activity: 6 Years ago

Since atomic radii of Noble gases are measured by vanderwaal radii so the atomic radii of neon is greater than fluorine

Attin singh

Last Activity: 6 Years ago

Neon belongs to vanded waal radius and flourine to covalent radius r vander is greater than r covalent ans. Is a

ankit singh

Last Activity: 4 Years ago

Atomic radii of fluorine and neon in angstrom units are respectively 0.42 and 0.38 amstrong. Atomic radius of fluorine is higher than neon because if we move from fluorine to neon one electron increases in the same valence shell. Hence the nuclear attraction towards valence shell increases.