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An electron has kinetic energy 2.8 x 10-23 J. de-Broglie wavelength will be nearly (me = 9.1 x 10-31 kg)

Nikhila Thakur , 7 Years ago
Grade 12th pass
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

de-Broglie wavelenngth = h/root(2*m*K.E.) => 6.64 x 10^-34/root(2*9.1*10^-31*2.8*10^-23) => 6.64 x 10^-34/7.53 * 10^-27 => 0.939 x 10^-7 m.
This would be the de-broglie length in meter.
and 939 in Angstorm.

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