Grade 12th passInorganic Chemistry
An electron has kinetic energy 2.8 x 10-23 J. de-Broglie wavelength will be nearly (me = 9.1 x 10-31 kg)
1 Answer
Vikas TU
de-Broglie wavelenngth = h/root(2*m*K.E.) => 6.64 x 10^-34/root(2*9.1*10^-31*2.8*10^-23) => 6.64 x 10^-34/7.53 * 10^-27 => 0.939 x 10^-7 m.
This would be the de-broglie length in meter.
and 939 in Angstorm.
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