An electic current of 0.5 ampere is passed through acidulated water for 30 minutes.calculate the volume of hydrogen produced at NTP.(z for hydrogen=0.00001)

Question

Aarti Gupta · Answer

Given &ndash; Current , I = 0.5A Time ,t = 30min Z for H2 = 0.00001 Volume ,V for hydrogen = ? SOLUTION - We know that , m = z *I * t Putting the respective values, m = 0.00001 * 0.5 * 30 m = 1.5 * 10-4 kg = 0.15g now, density = mass / volume therefore, Volume,V = mass / density Density of H2 gas at NTP = 0.089gm/l So, V = 0.15 / 0.089 V = 1.685ml or, V of H2 produces at NTP = 1.66ml

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An electic current of 0.5 ampere is passed through acidulated water for 30 minutes.calculate the volume of hydrogen produced at NTP.(z for hydrogen=0.00001)

An electic current of 0.5 ampere is passed through acidulated water for 30 minutes.calculate the volume of hydrogen produced at NTP.(z for hydrogen=0.00001)

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