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Grade: 12th pass
        
An atom has electronic configuration 1s2 2s2 2p6 3s2 3p6 3d3 4s2, you will place it in which group of periodic table ???
Β 
1. FifthΒ  Β  2. Fifteenth
3. SecondΒ  Β 4. Third
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Please solve with explanation and not by atomic number z=23 and this belong to this group like that............
Thanks a lot πŸ˜ŠπŸ‘πŸ‘πŸ‘πŸ‘πŸ˜πŸ˜
one month ago

Answers : (1)

Arun
22281 Points
							
The atomic configuration given = Β 1s2 2s2 2p6 3s2 3p6 3d3 4s2
We know that for neutral atoms the number of electrons is equal to the atomic number of the element.
Total no of electron = 2+2+6+2+6+3+2 = 23
=> atomic number of this element is 23
This number corresponds to Vanadium which is a transition metal located in fourth row, group 5 of the periodic table.
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one month ago
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