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An acid solution of 0.005 M has a pH of 5. The degree of ionization of acid is: An acid solution of 0.005 M has a pH of 5. The degree of ionization of acid is:
degree of ionizatio =c×¥=10^-5¥=degree of inizationc= .005 Mthererore ¥=10^-5/.005=2×10^-9thanks and regardssunil kraskIItian faculty
THIS IS CORRECT
0.999
degree of ionisation= 0.999
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