Grade 12Inorganic Chemistry
An acid solution of 0.005 M has a pH of 5. The degree of ionization of acid is:
6 Answers
Sunil Kumar FP
degree of ionizatio =c×¥=10^-5
¥=degree of inization
c= .005 M
thererore ¥=10^-5/.005=2×10^-9
thanks and regards
sunil kr
askIItian faculty
gokul
THIS IS CORRECT
yahwah nissi
0.999
yahwah nissi
0.999
yahwah nissi
0.999
yahwah nissi
degree of ionisation= 0.999
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