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An acid solution of 0.005 M has a pH of 5. The degree of ionization of acid is:

sanjeev100 , 11 Years ago
Grade 12
anser 6 Answers
Sunil Kumar FP

Last Activity: 11 Years ago

degree of ionizatio =c×¥=10^-5

¥=degree of inization
c= .005 M
thererore ¥=10^-5/.005=2×10^-9

thanks and regards
sunil kr
askIItian faculty

gokul

Last Activity: 10 Years ago

THIS IS CORRECT

yahwah nissi

Last Activity: 10 Years ago

0.999

yahwah nissi

Last Activity: 10 Years ago

0.999

yahwah nissi

Last Activity: 10 Years ago

0.999

yahwah nissi

Last Activity: 10 Years ago

degree of ionisation= 0.999

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