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Grade: 12 

                        
An acid solution of 0.005 M has a pH of 5. The degree of ionization of acid is:
6 years ago

Answers : (6)

Sunil Kumar FP
askIITians Faculty
183 Points 
							degree of ionizatio =c×¥=10^-5
¥=degree of inization
c= .005 M
thererore ¥=10^-5/.005=2×10^-9

thanks and regards
sunil kr
askIItian faculty
6 years ago
gokul
39 Points 
							
THIS IS CORRECT
6 years ago
yahwah nissi
33 Points 
							
0.999
6 years ago
yahwah nissi
33 Points 
							
0.999
6 years ago
yahwah nissi
33 Points 
							
0.999
6 years ago
yahwah nissi
33 Points 
							
degree of ionisation= 0.999
6 years ago
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