Grade 12th passInorganic Chemistry
Ammonium chloride is basic in nature.true or false?
Ammonium chloride is basic in nature.
true or false?
3 Answers
Rituraj Tiwari
NH4Clwhen dissolved in water undergoes cationic hydrolysis as follows:
NH4Cl→NH4++Cl−
Ammonium ion being a strong acid takesOH−ions furnished by water as :
NH4++H2O→NH4OH(freelyionized)+H+
Thus concentration ofOH−ions decreases and that ofH+ion increases due to cationic hydrolysis and consequently the solution become acidic in nature.
NH4Cl→NH4++Cl−
Ammonium ion being a strong acid takesOH−ions furnished by water as :
NH4++H2O→NH4OH(freelyionized)+H+
Thus concentration ofOH−ions decreases and that ofH+ion increases due to cationic hydrolysis and consequently the solution become acidic in nature.
ankit singh
Ammonium chloride is a neutral salt but its solution is slightly acidic because ammonium ion (NH4+) is a strong conjugate acid of a weak base ammonia and chloride ion (Cl−) is weak conjugate base of strong acid HCl
Vikas Amritiya
NH4Clwhen dissolved in water undergoes cationic hydrolysis as follows:
NH4Cl→NH4++Cl−
Ammonium ion being a strong acid takNH4Clwhen dissolved in water undergoes cationic hydrolysis as follows:
NH4Cl→NH4++Cl−
Ammonium ion being a strong acid takesOH−ions furnished by water as :
NH4++H2O→NH4OH(freelyionized)+H+esOH−ions furnished by water as :
NH4++H2O→NH4OH(freelyionized)+H+NH4Clwhen dissolved in water undergoes cationic hydrolysis as follows:
NH4Cl→NH4++Cl−
Ammonium ion being a strong acid takNH4Clwhen dissolved in water undergoes cationic hydrolysis as follows:
NH4Cl→NH4++Cl−
Ammonium ion being a strong acid takesOH−ions furnished by water as :
NH4++H2O→NH4OH(freelyionized)+H+esOH−ions furnished by water as :
NH4++H2O→NH4OH(freelyionized)+H+NH4Clwhen dissolved in water undergoes cationic hydrolysis as follows:
NH4Cl→NH4++Cl−
Ammonium ion being a strong acid takesOH−ions furnished by water as :
NH4++H2O→NH4OH(freelyionized)+H+
Ammonium ion being a strong acid takesOH−ions furnished by water as :
NH4++H2O→NH4OH(freelyionized)+H+
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