MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Amanat Grade: 12th pass
        
A solution of a metal ion when treated with KI gives a red precipitate which dissolves in excess KI to give a colourless solution. Moreover, the solution of metal ion on treatment with a solution of cobalt (II) thiocyanate gives rise to a deep blue crystalline precipitate.  The metal ion is
a. Pb^2+
b. Hg^2+
c. Cu^2+
d. Co^2+
3 years ago

Answers : (1)

bharat bajaj
IIT Delhi
askIITians Faculty
123 Points
										Hg (2+) + KI = HgI2 ( Red ppt.)
HgI2 + KI (excess) = K2HgI4

HgI^(2+) + Co(SCN)2 = Hg(SCN)2 Blue crystalline precipitate
B) is the answer
THanks
Bharat Bajaj
askiitians faculty
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details