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A sample of KCIO3 is 70% pure .The mass of impure KClO3 required to prepare 6.4g of oxygen is

A sample of KCIO3 is 70% pure .The mass of impure KClO3 required to prepare 6.4g of oxygen is

Grade:12

1 Answers

prince
15 Points
4 years ago
The ratio of K : Cl : O is 39 :36 :48
If O is 6.4g , the ratio will be now converted to 5.2: 4.8 : 6.4
Hence , the sum will be 16.4 g
But as KClO3 is only 70% pure , the required amount is 16.4/.7 = 23.42g of    KClO3.

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