A sample of h2o2 solution labelled as28 volume has density 26.5g/L what will be the molality

as indicated by the question 

This implies 1 volume of H2O2 will radiate 28 volumes of O2 at NTP,20C and at 1atm 

In this way, 1Litre of arrangement can deliver 28 liter of oxygen under these conditions 

give us a chance to expect that oxygen is an ideal gas,then from 

PV = nRT ,where P = 1atm and V = 28L 

with the goal that we can compute the n,ie number of moles of O2 

n = PV/RT 

n = 1X28/0.0821 X 298.15 

n = 1.144 moles of O2 

hydrogen peroxide disintegrates as 2H2O2 - >2H2O + O2 

Since double the quantity of moles are required to deliver 1 mole of oxygen so to produce 1.144 moles of O2 in 1L of solution,there must be 2.28 moles of H2O2 present in 1Litre 

So molarity of H2O2 is 2.28 

presently to compute molality 

molality = molarity X thickness 

= 2.28 X 26.5 

= 60.42g/L 

So malality = 60.42g/l