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a photon of 300nm is absorbed by a gas and then re emitts two photons.one reemitted photon has a wavelength of 500nm.calculate energy of other photon
@ roohinaya i am giving you the correct approach to solve this question . energy absorbed for photon = hc / lambda (1 ) = hc / 300 * 10 ^ -9 energy reemitted out for phtoton = hc / lambda (2) = hc / 500 * 10 ^-9 energy absorbed = energy for emitted photon = energy for 2nd emitted photon energy for 2nd emitted photon = hc / 500 * 10 ^ -9 now put the value of h as planks constant and c as the speed of light , then u will get the answer . HOPE IT CLEARS YOUR DOUBT ALL THE BEST ..
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