Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A mixture containing 2.24 L of H2 and 1.12 L of D2 at STP is taken insidea bulb connected to another bulb by a stopcock with a small opening. The second bulb is fully evacuated, the stopcock is opened for a certain time and then closed.After effusion the first bulb is found to comtain 0.1g of D2 . Find out the number of mole of H2 in second bulb.

A mixture containing 2.24 L of H2 and 1.12 L of D2 at STP is taken insidea bulb connected to another bulb by a stopcock with a small opening. The second bulb is fully evacuated, the stopcock is opened for a certain time and then closed.After effusion the first bulb is found to comtain 0.1g of D2 . Find out the number of mole of H2 in second bulb.

Question Image
Grade:11

1 Answers

varun
304 Points
3 years ago
HELLO ROHIT,
Molecular weight of H2 = 2 g/mol
Molecular weight of D2 = 2X2 = 4 g/mol
step 1
22.4L of H2 weighs = gm molecular weight of H2
                              =  2gm => 1mol
  So 2.24L of H2 weighs = 0.2gm => 0.1 mol
 
step 2
22.4L D2 weighs = gm molecular weight of D2
                          =      4gm => 1mol
So 1.12L of D2 weighs = 4g X 1.12L/22.4L
                                   =  0.2gm
Now,
0.2gm = 0.2g/4g/mol
           =  0.05 mol
this is the simplest way to solve this question
THANK YOU

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free