Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A gas cylinder contains 370g of O2 at 30 atm and 25`C. What mass of O2 would escape if first the cylinder was heated to 75`c and then the valve were held open until the gas pressure was 1atm, the temperature being maintained at 75`c?

A gas cylinder contains 370g of O2 at 30 atm and 25`C. What mass of O2 would escape if first the cylinder was heated to 75`c and then the valve were held open until the gas pressure was 1atm, the temperature being maintained at 75`c?

Grade:11

1 Answers

Arun
25763 Points
10 months ago
V1 = V2 cuz since you are using a gas cylinder, which is a rigid container, the volume won't change 
n1 = 370 g x 1mole / 32.0 g = 11.56 g 
T1 = 25 C = 298 K 
P1 = 30.0 atm 
n2 = ? 
T2 = 75 C = 348 K 
P2 = 1.00 atm 
R = 0.0821 L x atm / k x mole 
 
First find the volume of the container using the Ideal Gas Law 
 
P1V1 = n1RT1 
V1 = n1RT1 / P1 
V1 = 11.56 mole x (0.0821 L x atm / k x mole) x 298k /30.0 atm 
V1 = 9.43L 
 
Now find the number of mole in enviroment 2: 
P2V2 = n2RT2 
n2 = P2V2 / RT2 
n2 = 1.00 atm x 9.43L / ( ( 0.0821 L x atm / k x mole) x 348k) 
n2 = 0.330 mole 
 
n escaped = n1 - n2 
n escaped = 11.56 mole - 0.330 mole 
n escaped = 11.23 mole 
 
g escaped = 11.23 mole x 32.0 g / 1 mole 
g escaped = 359g .
 
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free