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A cylinder of gas is assumed to contain 11.2 kg of butane.If a normal family needs 20,000kJ of energy per day.The cylinder will last for how many days?(enthalpy for the combustion of butane is -2658kJ) ​20 days 35 days 26 days 31 days

Aishwarya Byreddy , 8 Years ago
Grade 12th pass
anser 1 Answers
Jayanth Kasaraneni

Last Activity: 8 Years ago

for 58 g of butane=2658KJ 
for 11200 g of butane =2658x193.10344826=513268.96550
no. of  days that on cylinder lasts is 513268.96550/20000=26 days(approx.)

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