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a compound contains 61%of carbon,11.88% hydrogen and 27.12%oxygen.if the volume density of compound is 59%.calculate the molecular formula.

a compound contains 61%of carbon,11.88% hydrogen and 27.12%oxygen.if the volume density of compound is 59%.calculate the molecular formula.

Grade:11

1 Answers

Vikas TU
14149 Points
one year ago
Dear student 
C=61/12=5.08
H=11.8/1=11.8
O=27/16=1.68
Lowest ratio value multiple to all value
C=5.08/1.68=3.02
H=11.8/1.68=7.2
O=1.68/1.68=1.68
Empirical formula is =C3H7O1
Empirical formula mass =3×12+7×1+1×16=59
n=density /emyrical formula mass =59/59=1
Molecular formula =n×emyrical formula =1×C3H7O1=C3H7O

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