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a compound contains 61%of carbon,11.88% hydrogen and 27.12%oxygen.if the volume density of compound is 59%.calculate the molecular formula.
Dear student C=61/12=5.08H=11.8/1=11.8O=27/16=1.68Lowest ratio value multiple to all valueC=5.08/1.68=3.02H=11.8/1.68=7.2O=1.68/1.68=1.68Empirical formula is =C3H7O1Empirical formula mass =3×12+7×1+1×16=59n=density /emyrical formula mass =59/59=1Molecular formula =n×emyrical formula =1×C3H7O1=C3H7O
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