a compound contains 61%of carbon,11.88% hydrogen and 27.12%oxygen.if the volume density of compound is 59%.calculate the molecular formula.

Question

Vikas TU · Answer

Dear student C=61/12=5.08 H=11.8/1=11.8 O=27/16=1.68 Lowest ratio value multiple to all value C=5.08/1.68=3.02 H=11.8/1.68=7.2 O=1.68/1.68=1.68 Empirical formula is =C3H7O1 Empirical formula mass =3×12+7×1+1×16=59 n=density /emyrical formula mass =59/59=1 Molecular formula =n×emyrical formula =1×C3H7O1= C3H7O

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a compound contains 61%of carbon,11.88% hydrogen and 27.12%oxygen.if the volume density of compound is 59%.calculate the molecular formula.

a compound contains 61%of carbon,11.88% hydrogen and 27.12%oxygen.if the volume density of compound is 59%.calculate the molecular formula.

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