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A certain inorganic compound (A) on heating loses its water of crystallization. On further heating, a blackish brown powder (B) and two oxides of sulphur (C and D) are obtained. The powder (B) on boiling with hydrochloric acid gives a yellow solution (E). When H 2 S is passed in (E) a white turbidity (F) and an apple green solution (G) are obtained. The solution (E) on treatment with thiocyanate ions gives a blood red coloured compound (H). Identify compounds from (A) to (H).

A certain inorganic compound (A) on heating loses its water of crystallization. On further heating, a blackish brown powder (B) and two oxides of sulphur (C and D) are obtained. The powder (B) on boiling with hydrochloric acid gives a yellow solution (E). When H2S is passed in (E) a white turbidity (F) and an apple green solution (G) are obtained. The solution (E) on treatment with thiocyanate ions gives a blood red coloured compound (H). Identify compounds from (A) to (H).

Grade:11

1 Answers

Aditi Chauhan
askIITians Faculty 396 Points
10 years ago
(i) Since the compound (A) on strong heating gives two oxides of sulphur (C and D) which might be SO2 and SO3, it must be a sulphate.
(ii) The reaction of compound (E) with thiocyanate to give blood red coloured compound (H) indicates that (E) must have Fe3+ ion.
Thus the compound (A) must be ferrous sulphate FeSO4. 7H2O, which explain all given reactions as below (Fe2+ ion of FeSO4 is changed to Fe3+ during heating).
FeSO4 7H2o \overset{heat}{\rightarrow}FeSO4 + 7H2O↑
Ferrous sulphate Ferrous
Sulphate
2 FeSO4 \overset{heat}{\rightarrow}Fe2O3 + SO2 + SO3
Ferrous Ferric (C)2 (D)3
Sulphate oxide,
(Blackish
Brown powder)
(B)
Fe2O3 + 6 HCI → 2FeCI3 + 3H2O
(B) Ferric chloride
(Yellow solution). (E)
2FeCI3 + H2S → 2FeCI2 + 2HCI + S
(E) Apple white
green (G) turbidity (F)
FeCI3 + 3NH4CNS → Fe (CNS)3 + Nh4CI
(E) Ferric thiocyanate
(blood red colour)

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