a binary salt potassium (A) on heating with sulphur gives a compund (B). (B) on reacting with bacl2 produces white percipitate which is insoluble in conc.hcl

indentifu A B C

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Here’s your answer:

 

 

 

Hence, when BaCl₂ is treated with (B), and a white precipitate (C) is produced which is insoluble in mineral acids, we can easily conclude that (C) is BaSO₄. And, since a binary salt of Potassium reacts with sulphur, the sulphate salt that reacts with BaCl₂ is Potassium Sulphate (B).

 

Also, we know that Potassium superoxide + Sulphur gives Potassium Sulphate:

2KO₂ + S ------> K₂SO₄.

 

So, (A) is KO₂.

 

 

A = KO₂

B = K₂SO₄

C = BaSO₄

 

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