5 moles of Na2S2O3 loses 40 moles of electron .Determine new oxidation no. of sulphur
Aryan Tripathi , 5 Years ago
Grade 11
Inorganic Chemistry> 5 moles of Na 2 S 2 O 3 loses 40 moles of...
1 Answers
Ravleen Kaur
Last Activity: 5 Years ago
2S2O3^(2-)===S406^(-2)+2e
Oxidation state of sulphur is 4x-12=-2
4x=+10
x=2.5
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