0

Guest

Courses New

1.The reaction,a+b------>c+d,proceeds to right hand upto 99.9%.Find the value of equilibrium constant. Ans:10^6 2.Kp for a reaction at 25`C is 10 atm.The activation energy for forward and reverse reactions are 12 and 20kJ mol respectively.Find Kc for the reaction at 40`C. Ans:3.33*10^-1M I wanted help with the method to solve it.Could you give the method in brief.Thanks!

1.The reaction,a+b------>c+d,proceeds to right hand upto 99.9%.Find the value of equilibrium constant.


   Ans:10^6


 


2.Kp for a reaction at 25`C is 10 atm.The activation energy for forward and reverse reactions are 12 and 20kJ mol respectively.Find Kc for the reaction at 40`C.


Ans:3.33*10^-1M


 


I wanted help with the method to solve it.Could you give the method in brief.Thanks!

Grade:11

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
9 years ago
the value of equilibrium constant will be

[c][d]/[a][b]
=99.9*99.9/.1*.1
=10^6

2

delta h for the reaction is Ef-Eb=12-20=-8kj/mol
Kp for the reaction is 10atm therefore delta n=1
now Kp=Kc(RT)deltan
=Kc=10/.0821*298=.4M
delta H for the reaction is -8Kj/mol
Kc at 40 c
log(k40/k25) =deltaH/2.303R(1/T1-1/T2)
K40 =.34m

Think You Can Provide A Better Answer ?

Other Related Questions on Inorganic Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More