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The value of Kp for the equilibrium of the reaction N 2 O 4 --------->2NO2 is 2 the the % dissociation of N 2 O 4 at 0.5 atm pressure will be A.25 B.68 C.71 D.82 Please help!

The value of Kp for the equilibrium of the reaction N2O4--------->2NO2 is 2 the the % dissociation of N2O4 at 0.5 atm pressure will be


A.25


B.68


C.71


D.82


Please help!


 

Grade:11

3 Answers

Shubham Mishra
16 Points
11 years ago

I am not writing the detailed answer but it is some where near to 68, i.e. B, however trick is to calculate the value of α by taking initial pressure of N2O0.5-(0.5alpha)....and then clalculate alpha by given Kp

Priyank singh
16 Points
11 years ago
the value comes out to be 70.92(approx.) hence the correct value is 71(most appropriate here) ,hence C is correct.
Palak J
14 Points
11 years ago

I wanted help with the method to solve it.Could you give the method in brief

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