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The value of Kp for the equilibrium of the reaction N2O4--------->2NO2 is 2 the the % dissociation of N2O4 at 0.5 atm pressure will be
A.25
B.68
C.71
D.82
Please help!
I am not writing the detailed answer but it is some where near to 68, i.e. B, however trick is to calculate the value of α by taking initial pressure of N2O4 0.5-(0.5alpha)....and then clalculate alpha by given Kp
I wanted help with the method to solve it.Could you give the method in brief
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