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The value of Kp for the equilibrium of the reaction N2O4--------->2NO2 is 2 the the % dissociation of N2O4 at 0.5 atm pressure will be

A.25

B.68

C.71

D.82

Please help!

Palak J , 16 Years ago
Grade 11
anser 3 Answers
Shubham Mishra

I am not writing the detailed answer but it is some where near to 68, i.e. B, however trick is to calculate the value of α by taking initial pressure of N2O4 0.5-(0.5alpha)....and then clalculate alpha by given Kp

Last Activity: 16 Years ago
Priyank singh
the value comes out to be 70.92(approx.) hence the correct value is 71(most appropriate here) ,hence C is correct.
Last Activity: 16 Years ago
Palak J

I wanted help with the method to solve it.Could you give the method in brief

Last Activity: 16 Years ago
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