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If the electronegativity difference between two atoms A and B is 2.0, then the percentage distribution character in the molecule is
(A) 54%
(B) 46%
(C) 23%
(D) 72%

Amit Saxena , 12 Years ago
Grade upto college level
anser 2 Answers
Radhika Batra

The percentage ionic character is related to electronegativity difference between the two atoms. It is given by Hannay and Smith relationship.

 

        %age ionic character.

 

                = 16 (XA − XB) + 3.5 (XA − XB)2

 

        Here, XA and XB are elecrtronegativities of two atoms A and B

 

        \ % ionic character = 16(2) + 3.5(2)2 = 46%

 

        or covalent character = 100 – 46 = 54%

Last Activity: 12 Years ago
naniuppati

b

Last Activity: 12 Years ago
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