If the electronegativity difference between two atoms A and B is 2.0, then the percentage distribution character in the molecule is (A) 54%(B) 46%(C) 23%(D) 72%

The percentage ionic character is related to electronegativity difference between the two atoms. It is given by Hannay and Smith relationship.

        %age ionic character.

                = 16 (X_A − X_B) + 3.5 (X_A − X_B)²

        Here, X_A and X_B are elecrtronegativities of two atoms A and B

        \ % ionic character = 16(2) + 3.5(2)² = 46%

        or covalent character = 100 – 46 = 54%

b