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One commercial system removes SO 2 emission from smoke at 95°C by the following set of reaction : Assuming the process to be 50% efficient. How many grams of CaSO 4 may be produced from 320 gm of SO 2 . SO 2 (g) + Cl 2 (g) → SO 2 Cl 2 (g) SO 2 Cl 2 (g) + H 2 O → H 2 SO 4 + HCl H 2 SO 4 + Ca(OH) 2 → CaSO 4 + H 2 O (1) 49 gm (2) 83 gm (3) 272 gm (4) 136 gm

One commercial system removes SO2 emission from smoke at 95°C by the following set of reaction :
Assuming the process to be 50% efficient. How many grams of CaSO4 may be produced from 320 gm of SO2.
SO2(g) + Cl2(g) → SO2Cl2(g)
SO2Cl2(g) + H2O → H2SO4 + HCl
H2SO4 + Ca(OH)2 → CaSO4 + H2O




















(1) 49 gm
(2) 83 gm
(3) 272 gm
(4) 136 gm

Grade:12

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
9 years ago
NO of mole in 320 gm of SO2 is 5 mole
since the process is 50%efficient therefore
5 mole of SO2 will produce 2.5 mole of so2cl2 which will produce 1.25 mole of Caso4 which will further produce .625 mole od CaSO4
molecular weight of CaSO4=136
therefore weight of CaSO4=.625*136 gm=85 gm

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