One commercial system removes SO2 emission from smoke at 95°C by the following set of reaction :Assuming the process to be 50% efficient. How many grams of CaSO4 may be produced from 320 gm of SO2.SO2(g) + Cl2(g) → SO2Cl2(g)SO2Cl2(g) + H2O → H2SO4 + HClH2SO4 + Ca(OH)2 → CaSO4 + H2O (1) 49 gm (2) 83 gm (3) 272 gm (4) 136 gm

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One commercial system removes SO₂ emission from smoke at 95°C by the following set of reaction :
Assuming the process to be 50% efficient. How many grams of CaSO₄ may be produced from 320 gm of SO₂.
SO₂(g) + Cl₂(g) → SO₂Cl₂(g)
SO₂Cl₂(g) + H₂O → H₂SO₄ + HCl
H₂SO₄ + Ca(OH)₂ → CaSO₄ + H₂O

(1) 49 gm

(2) 83 gm

(3) 272 gm

(4) 136 gm

anto frederick , 11 Years ago

Grade 12

1 Answers

Sunil Kumar FP

Last Activity: 10 Years ago

NO of mole in 320 gm of SO2 is 5 mole
since the process is 50%efficient therefore
5 mole of SO2 will produce 2.5 mole of so2cl2 which will produce 1.25 mole of Caso4 which will further produce .625 mole od CaSO4
molecular weight of CaSO4=136
therefore weight of CaSO4=.625*136 gm=85 gm