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Grade 12Inorganic Chemistry

One commercial system removes SO2 emission from smoke at 95°C by the following set of reaction :
Assuming the process to be 50% efficient. How many grams of CaSO4 may be produced from 320 gm of SO2.
SO2(g) + Cl2(g) → SO2Cl2(g)
SO2Cl2(g) + H2O → H2SO4 + HCl
H2SO4 + Ca(OH)2 → CaSO4 + H2O
(1) 49 gm
(2) 83 gm
(3) 272 gm
(4) 136 gm

Profile image of anto frederick
12 Years agoGrade 12
Answers icon

1 Answer

Profile image of Sunil Kumar FP
11 Years ago
NO of mole in 320 gm of SO2 is 5 mole
since the process is 50%efficient therefore
5 mole of SO2 will produce 2.5 mole of so2cl2 which will produce 1.25 mole of Caso4 which will further produce .625 mole od CaSO4
molecular weight of CaSO4=136
therefore weight of CaSO4=.625*136 gm=85 gm

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