volume of air required to oxidise 210ml sulphur dioxide to sulphur trioxide , if air has 21% oxygen
volume of air required to oxidise 210ml sulphur dioxide to sulphur trioxide , if air has 21% oxygen
sanjeev kumar , 12 Years ago
Grade 12
Inorganic Chemistry> mole-concept...
2 AnswersVikas TU
volume of air required to oxidise 210ml sulphur dioxide to sulphur trioxide , if air has 21% oxygen=
2SO2 + O2 -------> 2SO3
210 gm 0.21 ''a'' gm
210/(64 x 2) = 0.21a/(32 x 1)
AfTER solving x comes = 250 ml.
Thus it volume of air required to oxidise 210ml sulphur dioxide is 250 ml.
PLz Approve!
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adish
The equation for the following question is as follows:-SO2 +1/2O2 -----> SO3Therefore 1:1/2(21/100)*x = 210/2After solving x we get,x = 500ml
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