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The correct answer is a.In ClF3 all bonds are not equal due to trigonal-bipyramidal (sp^3d − hybridisation) geometry of ClF3 molecule.BF3 and AlF3 show trigonal symmetric structure due to sp^3 – hybridization.NF3 shows pyramidal geometry due to sp^3 hybridisation.
i think by bonds u mean bond lenghtsbond lenghts are equal when the bonds lie on the same plane,of all...CLF3 has 4 lone pairs and 3 bond pairs.as a result the structure is pentagonal biplanar. and the bond lenghts are not equal since two bond pairs are located at axial pos. and hence at different plane
are not equal since two bond pairs are located at axial pos. and hence at different plan
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