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hybridisation of ni in ni(co)4
in co ord compounds hybridisations of three types exist (mostly) sp3 dsp2 and sp3d2
ni z= 28 3d8 4s2
oxidation state 0 CO is neutral ligand and strong field ligand therefore e- pairing occurs and final e- config after pairing is
3d10 4s0 hence 4s and 4p orbitals will be used for bonding and no of ligand is 4 so
hybridisation sp3
sp3
Its sp3. The compound has a tetrahedral structure.
its Sp3
SP3.....us correct
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