#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# A sample of a compound consists of C , H and N only.If 24 gm of carbon , 6.022 x 1024 atoms of hydrogen and 2 -gm atom of nitrogen is present and vapour density of the compound is 16.5 , then its molecular formula will be ?

Shivam Dimri
43 Points
8 years ago

vapor density is 16.5

=> molecular mass should be 16.5 * 2 = 33

Now it has 24 gm carbon => 2x moles of carbon

2-gm atom of N = 2x moles of nitrogen

.

.

.

going this way the empirical mass> molecular mass

that immpossible

you posted a wrong question

check again!!

Akash Kumar Dutta
98 Points
8 years ago

given vapour density=16.5
so molecular mass= 2.d=33 gm
no. of moles of carbon=2
no. of moles of hydrogen=10
moles of nitrogen=2,
ratio of moles=2:10:2=1:5:1
but according to this the mass comes=31 gm.
hence the no of hydrogen req. more=2
so the formula becomes....
CH(7)N

tejas naresh patel
40 Points
8 years ago

the method i try to remove empirical formula

shiddhant bhattacharya
25 Points
8 years ago

is it CH5N

Saurabh Anand
38 Points
8 years ago

vapour density = molecular mass/2

so ur ans is....16.5*2 = 33g/mol

FITJEE
43 Points
7 years ago

CH5N

vishal ojha
35 Points
7 years ago

wrong question